Two fair 6-sided dice are rolled. What is the probability that the sum of the tw

Question

Two fair 6-sided dice are rolled. What is the probability that the sum of the two number on the die is greater than? Or multiple of 4? 1/2 1/16 2/3 5/6 Based on metrological records, the probability that it will snow in a certain town on January 1 st is 0.165. Find the probability that in a given year it will not snow on January 1 st in that know 0.165 0.616 0.835 0.198 A bag contains 6 red marbles, 3 blue marbles, and 5 green marbles. Two marble are picked at random without replacement what is the probability that both are green marbles? 25/196 10/91 5/14 10/14 Divide and write is scientific notation (6times 10^-9) (8 times 10^-15) 1.3 times 10^4 0.75 times 10^6 7.5 times 10^7 7.5 times 10^5 Find the standard deviation for the given data. Round your answer to nearest tenth 51 65 70 64 96 80 69 74 52 11.4 13.8 14.7 9.5 Use the compound interest formula for compounding more than once a year to determine the accumulated balance after the stated period Round to nearest hundredth $2500 deposit at an APR of 1.75% with semi-annually compounding for 9 years. $ 5.974.41 $ 5.951.97 $3, 864.71 $2.924.45

Explanation / Answer

10)

Possible outcome for sum greater than 7 are {(2,6) (3,5) (3,6) (4,4) (4,5) (4,6) (5,3) (5,4) (5,5) (5,6) (6,2) (6,3) (6,4) (6,5) (6,6)}

i.e. 15, hence P(A) = 15/36

Possible outcome for sum is multiple of 4 are {(1,3) (2,2) (2,6) (3,1) (3,5) (4,4) (5,3) (6,2) (6,6)}

i.e. 9, hence P(B) = 9/36

A and B = {(2,6) (3,5) (4,4) (5,3) (6,2) (6,6)} i.e. 6 hence P(A and B) = 6/36

Required probability P(A or B) = P(A) + P(B) - P(A and B) = 15/36 + 9/36 - 6/36 = 18/36 = 1/2 (Option A)

(12)

Probability of snow on January 1st p = 0.165

Probability of no snow on January 1st, 1 - p = 1 - 0.165 = 0.835 (Option C)

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.