Introduction to Geometry 250 46. Sphere: d 6.20 ft 47. Sphere with diamete 31 48

Question

Introduction to Geometry 250 46. Sphere: d 6.20 ft 47. Sphere with diamete 31 48. sphere with radius C In Exercises 49 through 49. A rectangular swin wide. It is bordere What is the perim 195 40.8 m perimeter around See Figure 6.60. 34. 11.1 in. 0.067 km 124 in. 0.118 km 81.2 cm 3.36 in. 37, 0.608 ft 50. A retaining w gular piece o wide. What 39. 51 Calculate th 2.76 m 2.76 m dius of 2.43 52. An isoscele 2.76 m of the two Find the l 5.86 ft 53. A circle is 7.13 ft ence is 1 In Exercises 41 through 48, find the volumes of the indicated diamete figures 54. If the di is in or 41. Rectangular solid: 2.00 m, w 1.50 m,

Explanation / Answer

34) Its a Trapezium whose parallel sides are 11.1 in and 12.4 in
   and Distance between these parallel sides = 36.8 in.
Area of Trapezium = 1/2 (sum of parallel sides ) * Distance between these parallel sides
   = 1/2 ( 11.1 + 12.4) * 36.8 in2
   = 1/2 * 23.5 * 36.8
   = 432.8 in2

35) it is a Circle of Radius, R = 3.36 in
Area of Circle = R2
= (3.36)2
=11.2896 in2

38) Diameter = .608 ft
Radius = .608/2 = .304 ft
     Area of Circle = R2
= (.304)2
=.92416 ft2
     

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.