Buy Cheap Game (2 players): Shuffle one deck of Fraction Bars, deal each player
ID: 3119105 • Letter: B
Question
Buy Cheap Game (2 players): Shuffle one deck of Fraction Bars, deal each player eight bars, and set the unused bars aside. Player A lays down one bar face up and names the fraction on his or her bar. Player B lays down a bar and names the fraction on his or her bar. If the shaded amount of Player B's bar is greater than or equal to that on Player A's bar. Player B wins both bars (and sets them aside). Otherwise, Player A wins the bars. This is the end of the first play. The player who won the two bars begins the next play. When the players have both used their eight bars, deal eight more bars from the unused bars to continue the game. After all of the bars have been played, the player with the most bars wins. Variation: For 3 players, deal five bars to each player and adjust the rules accordingly. Example: For the bars shown here, the second player can win two bars by playing any of the bars for the fractions 3/4, 7/12, 3/3, or 5/6. Play at least one full Buy Cheap game. What is the best bar for the second player to play in the example above? Suppose Player 2 in the example started the game. Explain why it might not be a good strategy to start the game by laying down the zero bar.Explanation / Answer
b> as we could see the bar that Player one laid down has no fractions that is there are no partitions.
now for player 2 to win the round he/she could use any of te four basr with fractions:
3/4 = .75
7/12 = .583
2/3 = .667
5/6 = .833
as the name of the game is buy cheap that is we could win the game by presenting a bar with the lowest fraction within our pack but this fraction shall be greater that that of the bar laid down by the other player
going by this the bs option for player B is to use the 7/12 fraction bar.
c> if player 2 starts and uses the zero bar then it'll be really easy for player 1 to win by presenting any bar within his/her pack of 8 bars which has a fraction.
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