The figure shows the graph of y=-ax(squared) +bx+c The points are marked on the

Question

The figure shows the graph of y=-ax(squared) +bx+c The points are marked on the graph. The area enclosed by the parabola, the X-axis and the lines x=-h and x=h may be given by the following Area=h/3(y0+4y1+y2) Find the area enclosed by f(x)=-5xsquared+10 the x-axis and the lines x=-1 and x=1

Explanation / Answer

Daer Stdent Thank you for using Chegg !! Given y=-ax(squared) +bx+c f(x)=-5xsquared+10 => a = 5 b = 0 c = 10 The area enclosed by the parabola, the X-axis and the lines x=-h and x=h may be given by the following Area=h/3(y0+4y1+y2) Given h = 1 From the figure y0 = f(-h) = f(-1) y0 = 15 From the figure y0 = f(0) y1= 10 From the figure y2 = f(h) = f(1) y2 = 15 Area = (1/3) * (15 + 4* 10 + 15) 23.33333 Solution

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