A market segment consists of 300 individuals. A Logit mode choice model (with pa
ID: 3110205 • Letter: A
Question
A market segment consists of 300 individuals. A Logit mode choice model (with parameter equal to 1) has been estimated for this market resulting in the following utility function: U= beta_m - 0.40C - 0.03 T, where C is out-of-pocket cost in $ and T is travel time in min. Values of beta_m are Bus: 0.00; Rail: 0.50; Car: 1.50. For a particular origin-destination pair, the cost of a car trip is 2S and the duration 8min, a rail trip is 1.50$ and 12min, while a bus takes 20min and costs 1.25$. a. Predict the number of trips for each mode. b. An increase in the price of gas changes the cost of car to 3$, while all other parameters remain constant. What is the % increase in the share of bus and rail?Explanation / Answer
Firstly determine the utility function
Um=m-0.40C-0.03T
C is out of pocket cost in dollars, and T is travel time, min
Min. Value m
For Bus transit 0.00
Rail transit 0.50
Auto 1.50
For Auto, T= 8min, C=$2
For Rail, T=12 min, C=$1.50
For Bus, T=20min, C=1.25
UB=B-0.40C-0.03T = 0-0.40x1.25-0.03x20= -1.10
UR=m-0.40C-0.03T= 0.50-0.40x1.50-0.03x12= -0.46
UA=m-0.40C-0.03T= 1.50-0.40x2-0.03x8= 0.46
e-1.10=0.33, e-0.46=0.63, e+0.42=1.58
The probability of different mode
PB=0.33/(0.33+0.63+1.58)=0.33/2.54=0.13
PR=0.63/(0.33+0.63+1.58)= = 0.245
PA=1.58/(0.33+0.63+1.58)= =0.622
No. of trips by each mode
TB = 300*0.13= 39
TR = 300*0.245 = 73.5
TA =300*0.622=186.6
b)
UB=B-0.40C-0.03T = 0-0.40x1.25-0.03x20= -1.10
UR=m-0.40C-0.03T= 0.50-0.40x1.50-0.03x12= -0.46
UA=m-0.40C-0.03T= 1.50-0.40x3-0.03x8= 0.06
e-1.10=0.33, e-0.46=0.63, e+0.06=1.06
The probability of different mode
PB=0.33/(0.33+0.63+1.06)=0.33/2.02=0.1633
PR=0.63/(0.33+0.63+1.06)=0.63/2.02=0.312
PA=0.06/(0.33+0.63+1.06)=0.06/2.02=0.03
No. of trips by each mode
TB = 300*0.1633= 48.99
TR = 300*0.312 = 93.6
TA =300*0.06=18
Hence, % increase in BUS = (48.99-39)100/39 = 25.61%
% increase in RAIL = (93.6-73.5)100/73.5 = 27.35%
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