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This question has to do with self-reducibility. Show how the optimization versio

ID: 3109732 • Letter: T

Question

This question has to do with self-reducibility.

Show how the optimization version of vertex cover problem is polynomial time-reducible to its decision version.

The optimization version, known as min vertex cover problem, is this --

“given a graph G, find the minimum set of vertices that cover all the edges in G”.

The decision version is this --

“given a graph G and a constant k, is there a vertex cover of at most k vertices?”

Here, we say a vertex “covers” an edge if and only if the vertex is an end-node of the edge.

Explanation / Answer

Consider the following solution of optimization version in terms of decision version:

for i = 1 to i = |V|

if there is a vertex cover of at most i vertices then return i

else increment i

This algorithm is linear reduction of optimization problem as for loop increases complexity by atmost(|V|) time.

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