Below is a DNA sequence that is a template strand and contains an Open reading f

Question

Below is a DNA sequence that is a template strand and contains an Open reading frame for a gene: 3' TAAATACCTGAGGGCCATAAAAGACCGCCACACTAATTT 5' Transcribe the open reading frame into a strand of mRNA by typing the mRNA sequence below the template strand. Highlight the start codon green in the mRNA and translate the mRNA. If there is a stop codon, highlight it red. What is the peptide encoded by this strand of mRNA? The base calling program made a mistake that you didn't catch and deleted the underlined G in the original template strand above. Copy the template below and delete the G. Transcribe and translate the resulting sequence. The base calling program made a mistake that you didn't catch and added an extra G after the underlined G in the original template strand above. Copy the template below and add an extra G. Transcribe and translate the resulting sequence.

Explanation / Answer

Answer

Transcription is process of synthesis an mRNA fron DNA strand. it is catalized by RNA Polymerase.

The transcribed mRNA of given DNA fragment is shown below:

3’ TAAATACC TGAGGGCCATAAAAGACCGCCACACTAATTT 5’

5' AUUUAUGGACUCCCGGUAUUUUCUGGCGGUGUGAUUAAA ‘3

Translation is the process of synthesising a polypeptide chain from mRNA molecule by ribosomes

Initiation Codon where translation starts is AUG

Termination codons where translation terminates are UAG, UAA and UGA

Translation of the mRNA With highlighted G residue

5   AUUU AUG GAC UCC CGG UAU UUU CUG GCG GUG UGA UUA AA ‘3

                    Met Asp Ser Arg Tyr Phe   Leu Ala   Val   Stop codon Polypeptide chain

Translation of the mRNA Without highlighted G residue

5   AUUU AUG GAC UCC CGG UAU UUU CUG GGG UGU GAU UAA A ‘3

Met Asp Ser Arg Tyr Phe   Leu Gly Cys Asp   Stop codon Polypeptide chain

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