2200=35(a)+50(z) 51= z+7 ? This is not the problem, it is what I tried to do. Ho

Question

2200=35(a)+50(z)
51= z+7 ? This is not the problem, it is what I tried to do. How do I do this?

Suppose your company takes in $2,220 in sales in one day at one of its cell phone stores. The price breakdown per phone is as follows:

Cell phone model A4: $35
Smartphone Z20: $50
Suppose that 51 total phones were sold, and that 7 more of the Z20 model were sold than the A4 model.

1. Set up the system of equations that needs to be solved to determine how many of each type of phone were sold. Give a clear definition of the variables in the system.
2. Solve the system of equations, showing clearly how the solution was determined, and state the results clearly in light of the real-world situation.

Explanation / Answer

For the purposes of this I'm going to say:

x- Model A4
y- smartphone z20

Two equations:

x + y = 51

$35x + $50y = $2220

Since we know that 7 more z20's were bought compared to the A4's we can substitute y in either equation to find x.

x + (x + 7) = 51. Solve for x.

2x = 44; add two x's together, subtract 7 from both sides

x=22

Now plug in the x you just found in the other equation to get y.

$35(22) + $50y = $2220, which equals 770 + $50y = $2220

$50y = $1450, subtract 770 from both sides

y = 29

you're teacher would probably want you to show all the work even though once you find 'x' all you have to do is add 7 to get 29 for 'y'. And i'm pretty sure you know how to state the results

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.