write an equation of the line that passes through (6,-10) and is perpendicular t

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Explanation / Answer

First find the slope of the two points of the line that is perpendicular. This will give you the slope you need. So (-4 - - 6)/(3 - 4) = -2 For the other line to be perpendicular you take the opposite and reciprocal. So the slope will be 0.5 Now that we have the slope we can find the line. (y1 - y2) = m(x1-x2) Plug in the point and slope y - - 10 = 0.5(x1 - 6) => y + 10 = 0.5(x-6) y = 0.5x -3 -10 y = 0.5x - 13 which goes through the line (6,-10) and is perpendicular to the line that goes through (4,-6) and (3,-4) you can check by 0.5(6) - 13 = -10 which checks. you could also find the equation of the other line by picking 1 point. -6 = -2(4) + b b = 2 So, the equation of the line is y = -2x + 2 You can graph them both and check if they are perpendicular.

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