I\'m having a hard time in my Algebra II class, sometimes I feel like I know wha

Question

I'm having a hard time in my Algebra II class, sometimes I feel like I know what I'm doing then I hit a wall and realize maybe I don't know after all. For some reason this problem is giving me a hard time, I can somewhat solve the other problems assigned for homework, but this one is difficult, can you help?

(2x+3y)=(10)
(x+6y)=(32) I'm having a hard time in my Algebra II class, sometimes I feel like I know what I'm doing then I hit a wall and realize maybe I don't know after all. For some reason this problem is giving me a hard time, I can somewhat solve the other problems assigned for homework, but this one is difficult, can you help?

(2x+3y)=(10)
(x+6y)=(32)

Explanation / Answer

This is two variables with two equations. Let's express both equations in terms of x: The first: 2x+3y=10 2x=10-3y x=5-3/2y The second: x+ 6y = 32 x=32-6y Each equations equals x, so both must equal each other: 5-3/2y=32-6y Subtract 5 from both sides: -3/2y=27-6y -27 = -6y + 3/2y -27 = -4.5y y=6 Now plug y = 6 into one of the equations: 2x+18=10 2x=10-18 2x=-8 x=-4 y=6 and x=-4

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