a. 80% + 1.8% b. 80% + 1.9% c. 80% + 2.6 % d. 80% + 3.3% e. 80% + 3.9% a. no mor

Question

a.       80% + 1.8%

b.      80% + 1.9%

c.       80% +2.6 %

d.      80% + 3.3%

e.       80% + 3.9%

a.       no more than 83% of thepopulation believe that teachers should be tested

b.      The actual parameter is between77% and 83%.

c.       It is unlikely that thereported statistic would be 80%, unless the true value was between77% and 83%

d.      3% of the people were notsurveyed

e.       3% of the time, the valueobtained could differ from 80%

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Explanation / Answer

1.) A recent USA Today survey of 400 people reportedthat 80%of American adults believe that teachers should be requiredto submit to random drug testing as a condition ofemployment. What is the 90% confidence interval?
Let x be binomial with n=400, p=.8, q=.2. Then =400(.8)=320ans =(400*.8*.2)=8 P(320-a<x<320+a)=.9 if we solve for a the320-a<x<320+a would be a 90% confidence interval P(320<x<320+a)= .45 by symmetry from above P(0<z<a/8)=.45 usin tables a/8=1.645 or a= 13.16 ans 320-13.16=306.84 to 333.16 is a 90% confidenceinterval 2.) A recent USA Today survey of 400 people reportedthat 80% of American adults believe that teachers should berequired to submit to random drug testing as a condition ofemployment. The margin of error was reported as 3%. Whatdoes this mean? means between 77 and 83%

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