A = $48,000 + [4/(4+3+3)] x IS IS = $72,000 + [4/(4+22+16)] x A 1) A = $48,000 +
ID: 3095572 • Letter: A
Question
A = $48,000 + [4/(4+3+3)] x ISIS = $72,000 + [4/(4+22+16)] x A
1) A = $48,000 + (4/10) x [$72,000+ (4/42) x A] 2) A = $48,000 + $28,800 +(16/420) x A] 3)(404/420) x A =$76,800 4)A = $76,800 x(420/404) = $79,842 5)IS = $72,000 + (4/42) x $79,842 =$79,604 I'm loss at step 3, where did 404/420 come from? A = $48,000 + [4/(4+3+3)] x IS
IS = $72,000 + [4/(4+22+16)] x A
1) A = $48,000 + (4/10) x [$72,000+ (4/42) x A] 2) A = $48,000 + $28,800 +(16/420) x A] 3)(404/420) x A =$76,800 4)A = $76,800 x(420/404) = $79,842 4)A = $76,800 x(420/404) = $79,842 5)IS = $72,000 + (4/42) x $79,842 =$79,604 I'm loss at step 3, where did 404/420 come from? I'm loss at step 3, where did 404/420 come from?
Explanation / Answer
From there, I think it is pretty clear
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