1. The sales tax on an $80 items was $5.2. Find the sales taxfor a $120 items. S
ID: 3093902 • Letter: 1
Question
1. The sales tax on an $80 items was $5.2. Find the sales taxfor a $120 items. Set up an equation to solve it. 2. If L varies inversely as W, and L=12, when W=5, find L whenW=15. 3. If gasoline costs 85 cents per liter, find the cost pergallon, give that 1gal=3.79 liter. 1. The sales tax on an $80 items was $5.2. Find the sales taxfor a $120 items. Set up an equation to solve it. 2. If L varies inversely as W, and L=12, when W=5, find L whenW=15. 3. If gasoline costs 85 cents per liter, find the cost pergallon, give that 1gal=3.79 liter.Explanation / Answer
1. First you need to find the percentage of sale tax.To do this set $80/100%=$5.2/x% then cross multiply to solve for x (sales tax percent) which 6.5% for sales tax. Now just find the 6.5% of $120 which is $120/100% = $x/6.5% cross multiply again and solve for x (amount of dollars) which gives you $7.8 of sales tax.
The equation could be: Sales tax = (x * 0.065) where x is the moneyspent on the items.
2. Since L varies inversely as W then that means that 1 / L = W However since it says that when L = 12, W =5 then you need anx on your equation. Therefore the true equation should be: x/L = W Since for the first part they give you L and W you can solvefor x x / 12 = 5 -----> x = 60
So now that you know x plug it in your equation: 60/L = W
So to find L when W = 15 plug it in:
60 / L = 15 -------> solving for L ------> L = 60/ 15 = 4
Thus $3.22/gallon.
Hope that helps!
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