For what value(s) of b does f have a jumpdiscontinuity at -4? f (x) = { -x + b i

Question

For what value(s) of b does f have a jumpdiscontinuity at -4?

f(x) = { -x + b if x < -4
          { 3 if x = -4
{ -3/(x - b) + 2 if x > -4(and x does not equal b)

Some answers I got that may help:
f is continuous at -4 when b equals -1.
f has an removable discontinuity at -4 when b equals-5.
f has an infinite discontinuity at -4 when b isequal to -4.

Explanation / Answer

I am pretty sure you just set up the limits as x-> -4 from theleft and right equal to each other. So, lim as x->-4 fromleft of (-x + b) = lim as x-> -4 from right of (-3/(x-b)). Then solve this for b once you plug in x = -4. I got thevalues to be -5 and -1. Hopefully you can also get these.

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