(x 2 -39) - (x-7 ) (x 2 + 3x -10) (x-2) I need to see the process, and please be
ID: 3093162 • Letter: #
Question
(x2-39) - (x-7)(x2 + 3x -10) (x-2) I need to see the process, and please be surethat the process is correct.
(I have the problem of mixing up steps, and I have it bad enoughalready)
If anyone can, please give me a hand. These problems aren't in anybook they're on a worksheet.
(Pg. R.5 can be a reference to lookat similar problems in the textbook listedbelow.
(x + 4) - (2x+3)
(x2 - x - 2) (x2 + 2x -8)
(x2 + 3x -10) (x-2) I need to see the process, and please be surethat the process is correct.
(I have the problem of mixing up steps, and I have it bad enoughalready)
If anyone can, please give me a hand. These problems aren't in anybook they're on a worksheet.
(Pg. R.5 can be a reference to lookat similar problems in the textbook listedbelow.
Explanation / Answer
[(x^2-39)-(x-7)(x+5)]/(x-2)(x+5) [x^2-39-x^2+2x+35]/(x-2)(x+5) [-4+2x]/(x-2)(x+5) [2x-4]/(x-2)(x+5) 2(x-2)/(x-2)(x+5) 2/(x+5) [(x+4)/(x+1)(x-2)]-[(2x+3)/(x+4)(x-2)] [(x+4)(x+4)-(2x+3)(x-1)]/(x+1)(x-2)(x+4) [x^2+8x+16-2x^2-x+3]/(x+1)(x-2)(x+4) [-x^2+7x+19]/(x+1)(x-2)(x+4)
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