Hello, Please help me solve this application problem. SPORTS: A pitcher releases
ID: 3092890 • Letter: H
Question
Hello, Please help me solve this application problem. SPORTS: A pitcher releases a baseball 6 feet above the groundat a speed of 132 feet per second (90 miles per hour) toward homeplate, which is 60.5 feet away. The height h(x), in feet, ofthe ball x feet from home plate can be approximated by h(x)=-0.0009x2 +6. To be considered a strike, the ballmust cross home plate and be at least 2.5 feet high and less than5.4 feet high. Assuming the ball crosses home plate, is thisparticular pitch a strike? Explain. Hello, Please help me solve this application problem. SPORTS: A pitcher releases a baseball 6 feet above the groundat a speed of 132 feet per second (90 miles per hour) toward homeplate, which is 60.5 feet away. The height h(x), in feet, ofthe ball x feet from home plate can be approximated by h(x)=-0.0009x2 +6. To be considered a strike, the ballmust cross home plate and be at least 2.5 feet high and less than5.4 feet high. Assuming the ball crosses home plate, is thisparticular pitch a strike? Explain.Explanation / Answer
I believe this question is worded incorrectly, so I willexplain it two ways.As worded: When the ball crosses home plate, its distance from home plate= 0, so x = 0. Plug in for h(x) to get h(0) = -0.0009 * (0)^2 + 6, so theanswer would be six feet, which doesn't make much sense, since thatis the height the pitcher threw the ball at.
Instead, I would assume it meant that x is the distance fromthe pitchers mound.
Therefore, the height would be h(x) for x = 60.5 (the distancefrom home plate to the pitcher) would be h(60.5) = -0.0009 * 60.5^2+6.
Good luck!
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