y- int 6, parallel to the line 2x+3y+4=0 First I rearranged the equation as y=-2

Question

y- int 6, parallel to the line 2x+3y+4=0
First I rearranged the equation as
y=-2/3x-4/3
Slope is -2/3
so I write it now in point form as y-6=-2/3(x-0)

Since I do not know what x1 is I assume its 0.
Please let me know if I did this right! Thank you WIll rate lifesavor, please explain why its right,
First I rearranged the equation as
y=-2/3x-4/3
Slope is -2/3
so I write it now in point form as y-6=-2/3(x-0)

Since I do not know what x1 is I assume its 0.
Please let me know if I did this right! Thank you WIll rate lifesavor, please explain why its right,

Explanation / Answer

The x value for any y int is 0

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