A Sports question: An arrow is shot into theair with an upward velocity of 48 ft

Question

A Sports question:    An arrow is shot into theair with an upward velocity of 48 ft/s                                from a hill 32 ft high. How many seconds later will the                                arrow be 64 ft above the ground?              h=32 +48t -16t2                                h is the height in feet AND t is the time inseconds A Sports question:    An arrow is shot into theair with an upward velocity of 48 ft/s                                from a hill 32 ft high. How many seconds later will the                                arrow be 64 ft above the ground?              h=32 +48t -16t2                                h is the height in feet AND t is the time inseconds                                h is the height in feet AND t is the time inseconds

Explanation / Answer

. 1.    In this problem substitute 64 feet for hand solve. . 2.   64 = 32 + 48t -16t2      ;  subtract 64 from both sides 3.   -16t2 + 48t - 32 =0      ;   divide throughby -16 4.   t2 - 3t + 2 =0      ;   factor 5.   (t - 1)*(t - 2) =0      ;   solve fort 6.   t =1   and    t = 2 7.   Thus, the arrow passes through 64 feet goingupward at 1 second and passes through 64 feet going downward at 2seconds. . 7.   Thus, the arrow passes through 64 feet goingupward at 1 second and passes through 64 feet going downward at 2seconds. .

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