the earth rotates on an axis thru it\'s poles. the distancefrom the axis to a lo
ID: 3092144 • Letter: T
Question
the earth rotates on an axis thru it's poles. the distancefrom the axis to a location on earth 30degrees north latitude isabout 3429.5miles. Therefore, a location on earth at 30 degreesnorth latitude is spinning on a circle of radius 3429.5 miles.Compute the linear speed on the surface of the earth at 30 degreesnorth latitude. I got this far: s=r 30 degrees= /6=.523 so .523 x 3429.5 = 1793.629 1793.629/T I have a feeling I'm doing something wrong but I can't figureit out the answer in the back of the book is 898 mi/hr Please help! the earth rotates on an axis thru it's poles. the distancefrom the axis to a location on earth 30degrees north latitude isabout 3429.5miles. Therefore, a location on earth at 30 degreesnorth latitude is spinning on a circle of radius 3429.5 miles.Compute the linear speed on the surface of the earth at 30 degreesnorth latitude. I got this far: s=r 30 degrees= /6=.523 so .523 x 3429.5 = 1793.629 1793.629/T I have a feeling I'm doing something wrong but I can't figureit out the answer in the back of the book is 898 mi/hr Please help!Explanation / Answer
This problem is a little tricky, because they give you moreinformation than you need. You know the speed is distance over time. So, you need to find thedistance traveled in one rotation of the Earth and the time ittakes to make one rotation. The distance is just the circumference of the circle formed by thegiven radius. C= 2*r = 2*(3429.5 miles) ˜ 21548 miles Since the period of rotation is T = 24 hours, the speed is v = C/T= (21548 miles)/(24 hours) ˜ 898 mi/hr.
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