1. candy selling for $2.00 per pound will be mixed with candyselling for $6.00 p

Question

1. candy selling for $2.00 per pound will be mixed with candyselling for $6.00 per pound. How many pounds of the moreexpensive candyh will be needed to produce a 24-pound mixture thatwill sell for $5.00 per pound? 2. A man went on a trip of 120 miles, traveling at an averageof x miles per hour. Several days later he returned ovwer the sameroute at a rate that was 5 miles per hour faster than his previousrate. If the time for the return trip was one-third of an hour lessthan the time for the outgoing trip, which equation can be used tofind the value of x? a. 120/(x+5)=1/3   b. x/120=(x+5)/120-1/3 c. 120/x+(x+5)=1/3     d.120/x=120/(x+5)+1/3      e.120(x+5)-120x=1/3 1. candy selling for $2.00 per pound will be mixed with candyselling for $6.00 per pound. How many pounds of the moreexpensive candyh will be needed to produce a 24-pound mixture thatwill sell for $5.00 per pound? 2. A man went on a trip of 120 miles, traveling at an averageof x miles per hour. Several days later he returned ovwer the sameroute at a rate that was 5 miles per hour faster than his previousrate. If the time for the return trip was one-third of an hour lessthan the time for the outgoing trip, which equation can be used tofind the value of x? a. 120/(x+5)=1/3   b. x/120=(x+5)/120-1/3 c. 120/x+(x+5)=1/3     d.120/x=120/(x+5)+1/3      e.120(x+5)-120x=1/3

Explanation / Answer

1) 6x+2(24-x)=5*24       6x+48-2x=120       4x=120-48          4x=72          x=18 2) d   Distance/ speed = time

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