1. The measure of the base of an isosceles triangle is 2in. less than the sum of
ID: 3091951 • Letter: 1
Question
1. The measure of the base of an isosceles triangle is 2in. less than the sum of the lengths of the two legs. If theperimeter of the triangle is 22 in., find the length of the base ofthe triangle. 2. Two sides of a triangle are equal in measure. Thelength of the third side exceeds the length of each of the equalsides by 3 inches. The perimeter of the triangle is 21 inches. Findthe length of each of the equal sides.. 1. The measure of the base of an isosceles triangle is 2in. less than the sum of the lengths of the two legs. If theperimeter of the triangle is 22 in., find the length of the base ofthe triangle. 2. Two sides of a triangle are equal in measure. Thelength of the third side exceeds the length of each of the equalsides by 3 inches. The perimeter of the triangle is 21 inches. Findthe length of each of the equal sides..Explanation / Answer
Question 1:Let a is the base of the isosceles triangle. b is the leg (orthe side) of the isosceles triangle. We have a = (b + b) -2 or a = 2b -2 (1) Otherwise, a + b+ b =22 => a + 2b =22 (2) Sustitute (1) into (2) : 2b - 2 + 2b = 22 4b -2 =22 4b = 24 b =6 => a = 2b- 2 = 2(6) - 2 => a = 12-2 = 10 => the base is 10 inches Question 2: Let a is the base (or the third side ) of thetriangle. b is the leg (orone side) of the triangle. We have: a = b + 3 anda + b + b = 21 =>b+ 3 + b + b =21 => 3b +3 = 21 => 3b =18 => b = 6 => a = b + 3 = 6 + 3 = 9 inches So, the base is 9 inches , and each side is 6inches. Let a is the base (or the third side ) of thetriangle. b is the leg (orone side) of the triangle. We have: a = b + 3 anda + b + b = 21 =>b+ 3 + b + b =21 => 3b +3 = 21 => 3b =18 => b = 6 => a = b + 3 = 6 + 3 = 9 inches So, the base is 9 inches , and each side is 6inches. We have: a = b + 3 anda + b + b = 21 =>b+ 3 + b + b =21 => 3b +3 = 21 => 3b =18 => b = 6 => a = b + 3 = 6 + 3 = 9 inches So, the base is 9 inches , and each side is 6inches.
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