Find an equation of the line that bisects the obtuse angles formedby the lines w

Question

Find an equation of the line that bisects the obtuse angles formedby the lines with equations 3x-y=1 and x+y=-2. a. (32+10)x-(10+ 2)y-210+2=0 b. (32- 10)x+(10- 2)y+210+2=0 c. (32+ 10)x+(10 - 2)y+210- 2=0 d. (32+ 10)x-(10+ 2)y-210-2=0 Find an equation of the line that bisects the obtuse angles formedby the lines with equations 3x-y=1 and x+y=-2. a. (32+10)x-(10+ 2)y-210+2=0 b. (32- 10)x+(10- 2)y+210+2=0 c. (32+ 10)x+(10 - 2)y+210- 2=0 d. (32+ 10)x-(10+ 2)y-210-2=0 a. (32+10)x-(10+ 2)y-210+2=0 b. (32- 10)x+(10- 2)y+210+2=0 c. (32+ 10)x+(10 - 2)y+210- 2=0 d. (32+ 10)x-(10+ 2)y-210-2=0

Explanation / Answer

Are you sure the question says obtuse? None of the answers arecorrect...but if the angle is acute, the answer is C 3x -y = 1 -> -y=1-3x -> y=3x-1 x + y = -2 -> y= -x-2 3x-1 = -x-2 4x = -1 x= -1/4 y= -x-2 = -(1/4) -2 = -7/4 Point of intersection: (-1/4, -7/4) Plug it into the four choices Only C works out: (32 + 10)(-1/4)+(10- 2)(-7/4)+210 - 2=0

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