It\'s a lot, but Please please please Help! Math Question. Truthin Advertising?

Question

It's a lot, but Please please please Help! Math Question. Truthin Advertising?

Watch this 30 second video first please..
http://www.youtube.com/watch?v=oRLqVlHzn...
It's the commercial the problem is on. It won't take long towatch.

"Use the Falling Object Equation;
h=-16t2 +s
to find how much time (t) it takes for the Lexus #1 to fall 4,000feet. ( The time will be in seconds)


Use the distance formula to find how fast, in miles per hour, theLexus #2 needs to travel in order to beat the falling Lexus #1.
The time for the Lexus #2 needs to be a little less, since it needsto get past the target before the falling Lexus hits theground."
I'm totally stuck, I did the falling object equation like this..:
0=16t2 + 4,800
4,800= -16t2 -300=t2
t= 17.320508
rounded to 17.3 seconds from 4,800 feet.
THEN...
I did the distance formula
4,800=4(16)
3=r
I have NO CLUE what to do from here.
Please please please please help! D':
Watch this 30 second video first please..
http://www.youtube.com/watch?v=oRLqVlHzn...
It's the commercial the problem is on. It won't take long towatch.

"Use the Falling Object Equation;
h=-16t2 +s
to find how much time (t) it takes for the Lexus #1 to fall 4,000feet. ( The time will be in seconds)


Use the distance formula to find how fast, in miles per hour, theLexus #2 needs to travel in order to beat the falling Lexus #1.
The time for the Lexus #2 needs to be a little less, since it needsto get past the target before the falling Lexus hits theground."
I'm totally stuck, I did the falling object equation like this..:
0=16t2 + 4,800
4,800= -16t2 -300=t2
t= 17.320508
rounded to 17.3 seconds from 4,800 feet.
THEN...
I did the distance formula
4,800=4(16)
3=r
I have NO CLUE what to do from here.
Please please please please help! D':

Explanation / Answer

without knowing the average speed of the falling lexus you can'tproperly exstimate the needed speed of the falling car. Inorder to do so you need to know not only the terminal velocity(maximum speed of the car) but also its acceleration rate to saidvelocity. The assumed wind conditions and altitute of thetest would all affect the calculations. Unless yourteacher specified any of these conditions you can't really find aanswer.

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