factor x 9 +y 9 i tried solving it = cubes so i solved like this(x 3 ) 3 +(y 3 )
ID: 3090441 • Letter: F
Question
factor x9+y9 i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) ' factor x9+y9 i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) ' i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) 'Explanation / Answer
Again book is right
you did:
(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)
if u see clearly in questn then u will notice that theterm (x3+y3) can again be factorizedas:
=> (x3+y3) =(x+y)(x2-xy+y2)
so the final answer will be;
x9+y9 =(x+y).(x2-xy+y2).(x6-x3y3+y6) That is thebook answer
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