TESTSCORE FREQUENCY 100 2 95 3 90 7 85 8 80 7 75 3 1. USE FREQUENCY TABLE 1 TO F
ID: 3089610 • Letter: T
Question
TESTSCORE FREQUENCY 100 2 95 3 90 7 85 8 80 7 75 3 1. USE FREQUENCY TABLE 1 TO FIND THE MEAN. 2. USE FREQUENCY TABLE 1 TO FIND THE MEDIAN 3. USE FREQUENCY TABLE 1 TO FIND THE MODE. 4. IF THE LOWEST TEST SCORE SHOWN IN FREQUENCY TABLE 1 HADBEEN 70 INSTEAD OF 75, WHICH WOULD BE TRUE, AND WHY? lowermedian--80 lowermean--85.5 highermedian--30 highermean--90 TESTSCORE FREQUENCY 100 2 95 3 90 7 85 8 80 7 75 3 1. USE FREQUENCY TABLE 1 TO FIND THE MEAN. 2. USE FREQUENCY TABLE 1 TO FIND THE MEDIAN 3. USE FREQUENCY TABLE 1 TO FIND THE MODE. 4. IF THE LOWEST TEST SCORE SHOWN IN FREQUENCY TABLE 1 HADBEEN 70 INSTEAD OF 75, WHICH WOULD BE TRUE, AND WHY? lowermedian--80 lowermean--85.5 highermedian--30 highermean--90Explanation / Answer
The mean is simply the average of the test scores for thepopulation; thus, mean = 2*100+3*95+7*90+8*85+7*80+3*75 = 2580/30 = 86 mean = 86 If the population is arranged in ascending order of magnitued,then the median is givn by the (n+1)/2 value; when n is odd themedian is the middle value of the set of ordered data; when n iseven, the median is usually taken as the mean of the two middlevalues of the set of ordered data. median =85, (value #15 = 85; and value #16 = 85) The mode is the value that occurs with the greatest frequency,i.e., the most common value. mode = 85 Only the mean would change: mean = 2*100+3*95+7*90+8*85+7*80+3*70 = 2565/30= 85.5 mean = 85.5 Only the mean would change: mean = 2*100+3*95+7*90+8*85+7*80+3*70 = 2565/30= 85.5 mean = 85.5Related Questions
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