1. WHEN A SAMPLE WAS SURVEYED ON THEIR PREFERENCE FOR YOGURTFLAVOR, 12 SAID VANI

Question

1. WHEN A SAMPLE WAS SURVEYED ON THEIR PREFERENCE FOR YOGURTFLAVOR, 12 SAID VANILLA AND 8 SAID BANANA. THE TOTAL GROUP WAS 160.HOW MANY PEOPLE WERE IN THE SURVEY? 2. WHAT IS THE PROBABILITY THAT A PERSON PREFERSVANILLA? 3.PREDICT HOW MANY PEOPLE OF THE 160 PREFER VANILLA. 1. WHEN A SAMPLE WAS SURVEYED ON THEIR PREFERENCE FOR YOGURTFLAVOR, 12 SAID VANILLA AND 8 SAID BANANA. THE TOTAL GROUP WAS 160.HOW MANY PEOPLE WERE IN THE SURVEY? 2. WHAT IS THE PROBABILITY THAT A PERSON PREFERSVANILLA? 3.PREDICT HOW MANY PEOPLE OF THE 160 PREFER VANILLA.

Explanation / Answer

1. The sample size of the survey was20. 12 + 8 =20. 2. Based upon the sample 12 of the 20 people surveyedlike vanilla. Therefore, the probability that a person chosenat random likes vanilla is: 12/20 = 0.60 3. Given a population of 160 people that prefer vanillaover banana with a probability of 0.60, the quantity of individualswithin the population that like vanilla is: (0.60)*(160 people) = 96 3. Given a population of 160 people that prefer vanillaover banana with a probability of 0.60, the quantity of individualswithin the population that like vanilla is: (0.60)*(160 people) = 96

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