One drain pipe can empty a swimming pool in 6 h. anotherpipe takes 3 h. If both

Question

One drain pipe can empty a swimming pool in 6 h. anotherpipe takes 3 h. If both pipes are used at the same time todrain the pool, what part of the job is completed in 2hours?   In x hours? Solve, show each step, make achart.                                                 Work rate   X       Time   =     Work Done                          Pipe 1                          Pipe 2 One drain pipe can empty a swimming pool in 6 h. anotherpipe takes 3 h. If both pipes are used at the same time todrain the pool, what part of the job is completed in 2hours?   In x hours? Solve, show each step, make achart.                                                 Work rate   X       Time   =     Work Done                          Pipe 1                          Pipe 2

Explanation / Answer

to solve this problem, simply fill in the chart. The rates are asfollows; pipe one empties 1 full pool in 6 hours, so its rate is1pool per 6 hours, and pipe 2's rate is 1 pool per 3 hours:                  Work Rate     X    Time     =     WorkDone Pipe 1         1pool/6h              2h                  1/3 Pipe 2         1pool/3h               2h                +2/3                                                                          1 pool So in 2 hours, working together, these two pipes drain the wholepool. To find the work done in "x" hours, we replace the 2hourswith "x" :                  Work Rate     X    Time     =     WorkDone Pipe 1         1pool/6h              xh                  x/6 Pipe 2         1pool/3h               xh                +x/3                                                                         x/6 + x/3 = 3x/6 = x/2 pools

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