I am having trouble with this practice homework problem anyhelp would be appreci

Question

I am having trouble with this practice homework problem anyhelp would be appreciated. A pie-shaped concert hall is constructed so that the back wallis an arc of a circle and the side walls meet at a point behind thestage. The length of arc along the back wall is 148feet. The front of the stage is 75 feet from the back walland is 30 feet from the point where the side walls meet behind thestage. How much area is available for seating in the concerthall? Give your answer to the nearest squarre foot. Thanks I am having trouble with this practice homework problem anyhelp would be appreciated. A pie-shaped concert hall is constructed so that the back wallis an arc of a circle and the side walls meet at a point behind thestage. The length of arc along the back wall is 148feet. The front of the stage is 75 feet from the back walland is 30 feet from the point where the side walls meet behind thestage. How much area is available for seating in the concerthall? Give your answer to the nearest squarre foot. Thanks

Explanation / Answer

2R*(/360)=148 [75]^2+[30/2]^2=R^2 R=76.49 ft =[148*360]/2(76.49)=348.28 Degree Area=2R^2*348.28/360=35564.38 ft^2 Hope it was helpful.

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