Solve the equation for x. x/5-1=-4 How much of an alloy that is 40% copper shoul

Question

Solve the equation for x. x/5-1=-4 How much of an alloy that is 40% copper should be mixed with100 ounces of an alloy that is 60% copper in order to get an alloythat is 50% copper? Translate to an equation and solve. Let x be the unknownnumber. 46 is 2% of what number? Solve the equation for x. x/5-1=-4 How much of an alloy that is 40% copper should be mixed with100 ounces of an alloy that is 60% copper in order to get an alloythat is 50% copper? Translate to an equation and solve. Let x be the unknownnumber. 46 is 2% of what number?

Explanation / Answer

    This looks like 3 problems, and there'sonly supposed to be one per post, so I'll take the one that looksmost troublesome. "How much of an alloy that is 40% copper should be mixed with100 ounces of an alloy that is 60% copper in order to get an alloythat is 50% copper? "    Translate to anequation and solve. Let x be the unknown number.        For this type of problem,use the basic concept that amount * percent + amount * percent = amount * percent so ...   100 oz. (60%) + x(40%) = (100 +x)(50%)       (the resulting "amount"is the total weight of both alloys on the left side of theequation.)       Turn the percentages intodecimal form and solve.                                 100(.6) + x (.4) = (100 +x)(.5)        Firstdistribute:               60   + .4x   = 50 +.5x      Now put all   x terms on one side bysubtracting 50 from each side,and subtracting .4x   from eachside.   60 - 50 = .5x - .4x 10 = .1x Now multiply both sides by 10 to get x. Have fun with this! "How much of an alloy that is 40% copper should be mixed with100 ounces of an alloy that is 60% copper in order to get an alloythat is 50% copper? "    Translate to anequation and solve. Let x be the unknown number.        For this type of problem,use the basic concept that amount * percent + amount * percent = amount * percent so ...   100 oz. (60%) + x(40%) = (100 +x)(50%)       (the resulting "amount"is the total weight of both alloys on the left side of theequation.)       Turn the percentages intodecimal form and solve.                                 100(.6) + x (.4) = (100 +x)(.5)        Firstdistribute:               60   + .4x   = 50 +.5x      Now put all   x terms on one side bysubtracting 50 from each side,and subtracting .4x   from eachside.   60 - 50 = .5x - .4x 10 = .1x Now multiply both sides by 10 to get x. Have fun with this!

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