dx/dt = x+2y-z dy/dt=-x+y+z dz/dt=2x+2y-2z I understand the top three-fourth of
ID: 3080608 • Letter: D
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dx/dt = x+2y-z dy/dt=-x+y+z dz/dt=2x+2y-2z I understand the top three-fourth of the problem; that is I know L1 (lamda) =0, L2=-1, l3=1 I also know that I have to plug each of these lamda values in the matrix to come up with K1, K2, K3 What I don't understand is and I have not read the rhyme and reasons as to what the goal is for the reduced matrix to look like. Do I have to get all ones in the matrix For example, when L1=0, this person has reduced the matrix as sollow: 1 0 -1 0 1 0 1 0 -1 then it says that the eigen vector is: 1 0 1 How do I know to reduce the above matrix as far as he did? where are the values 1, 0, 1 are coming from for the eigen vector shown above. Are you getting them from looking at the matrix above? Appreciate help. Please!Explanation / Answer
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