For a certain river, suppose the drought length Y is the number of consecutive t
ID: 3074876 • Letter: F
Question
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains below a critical value y (a deficit), preceded by and followed by periods in which the supply exceeds this critical value (a surplus). An article proposes a geometric distribution with p0.388 for this random variable. (Round your answers to three decimal places.) (a) What is the probability that a drought lasts exactly 3 intervals? At most 3 intervals? exactly 3 intervals at most 3 intervals (b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation? Need Help? ReadIt Taik to a TutorExplanation / Answer
a)
P(X = x) = q^x * p
P(X = 3) = (1 - 0.388)^3 * 0.388
= 0.08893
at most 3 interval
P(X <= 3) = P(X = 0) + P(X = 1) +P(X = 2) +P(X = 3)
= 0.388 + 0.612 * 0.388 + 0.612^2 * 0.388 + 0.08893
=0.859709072
b)
mean = (1- p)/p = 0.612/0.388 = 1.5773195
sd = sqrt( (1-p)/p^2) = sqrt(0.612/0.388^2) = 2.016248
P(X > 1.577 + 2.016)
= P(X > 3.593)
= P(X >=4)
= 1 - P(X <= 3)
= 1 - 0.8597090
=0.140291
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