17-1KTThe histogrem below meprsents scores achieved by 30 yh pplicents om 17) Re

Question

17-1KTThe histogrem below meprsents scores achieved by 30 yh pplicents om 17) Referring to the histogram, percent of the job applicant sconed below 501) A)20% B)60% C)80% D)50% 18) Referring to the histogram 70% ofthe applicants scored above. 5) -O) 20 A) 40 B) 50 C) 30 19) It is believed that 33% cf the population of an Business Statistics i students would likely to make 19) an A in the subject. Suppose we randomly selected five students from the populton,and the probability of observing between one and three (the endpoints are included) students who would make an A in the subject A) 0.8214 8) 0.3275 C) 0.5650 D) 0.4938 20) It is believed that33% of the population of all Business Statistics i students would likely to make an- an A in the subject. Suppose we randomly selected five students from the population. The average value that you would expect is A) 2.67 B) 1.86 C) 1.65 D) 5.33

Explanation / Answer

HISTOGRAM

from the histrogram we see that frequence is already computed in probability values,
Q17.
the no.of applicants scored below 50 = 0.10 + 0.20 + 0.20 + 0.10 + 0.20 = 0.80 = 80% scored below 50
Q18.
from the histrogram we cleary see that sum of probabilities above 20 is equals to 70%
P(X>=20) = 0.20 + 0.10 + 0.20 + 0.10 + 0.10
70% of the appplicants scored above 20
Q19.
BIONOMIAL DISTRIBUTION
pmf of B.D is = f ( k ) = ( n k ) p^k * ( 1- p) ^ n-k
where
k = number of successes in trials   
n = is the number of independent trials   
p = probability of success on each trial
X ~ B ( 5, 0.33)
P( X = 1 ) = ( 5 1 ) * ( 0.33^1) * ( 1 - 0.33 )^4
= 0.332493
P( X = 2 ) = ( 5 2 ) * ( 0.33^2) * ( 1 - 0.33 )^3
= 0.327531
P( X = 3 ) = ( 5 3 ) * ( 0.33^3) * ( 1 - 0.33 )^2
= 0.161321
P(1 < = X <=3 ) = 0.332493 + 0.327531 + 0.161321 = 0.8214
Q20.
mean = np
where
n = total number of repetitions experiment is excueted
p = success probability
mean = 5 * 0.33
= 1.65

Intervals P(X) 0-10 0.1 10-20 0.2 20-30 0.2 30-40 0.1 40-50 0.2 50-60 0.1 60-70 0.1

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