3. (3 points, 27 points cumulative) Start with a population of 100 individuals.
ID: 3074773 • Letter: 3
Question
3. (3 points, 27 points cumulative) Start with a population of 100 individuals. The population has no age structure. Nobody dies. Over each time interval, each individual has a probability of 0.40 of producing a single offspring. The expected geometric growth rate of this population per time interval is (circle one): 0.25 0.75 1.0 1.40 1.80 4. (3 points, 30 points cumulative) Suppose that a population is growing at a geometric rate of 2.718 each year. What is the corresponding exponential growth rate of the population per month (circle one)? 0.27 0.20 0.15 0.083 0.027 5. (3 points, 33 points cumulative) What is the expected doubling time in months of the population with an annual geometric growth rate of = 1.414 (circle one) 2.4 6 9.5 12 24 6. (3 points, 36 points cumulative) If an exponentially growing population had an initial size of 1000 individuals and an annual growth rate of = 16, how many would you expect in the population in 6 months (circle one)? 1200 1800 2500 4000 6500Explanation / Answer
HERE STARRTING WITH 100 INDIVIDUALS PROBABILITY OF A SINGLE OFFSPRING IS 0.40 WHERE NOBADY DIES.
THIS MEANS OUT OF 100 , 40 WILL GIVE NEW SINGLE OFFSPRING THUS LEADING TO A TOTAL POPULATION OF 140 FROM 100 IN A SINGLE TIME INTERVAL.
SO THE GROWTH RATE IS NEW POPULATION/OLD POPULATION
WHICH IS 140/100 THAT IS 1.40 IS THE GROWTH RATE HERE
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