positive values represent lengths of delays. Find the range, variance, and stand
ID: 3073946 • Letter: P
Question
positive values represent lengths of delays. Find the range, variance, and standard deviation for the set of data. Some of the sample values are negative, but can the standard deviation ever be negativel -30 -28 10 25 The range of the sample data is minutes. The variance of the sample data iminues (Round to one decimal place as needed) The standard deviation of the sample data is minutes (Round to one decimal place as needed.) O Yes, because the squared O Yes, because the squared value in the standand deviation formula can be negative. O No, because the squared value in the standard deviation formula can be negative. O No, because the squared value in the standard deviation formulia cannot be negative value in the standard deviation formula cannot be negative.Explanation / Answer
Ans:
Range=-4-(-30)=26.0
Sample Variance=641.33/(6-1)=128.3
Sample standard deviation=sqrt(128.3)=11.3
xi (xi-(-15.667))^2 1 -30 205.443 2 -5 113.778 3 -28 152.110 4 -10 32.111 5 -4 136.112 6 -17 1.778 Total -94 641.333 mean= -15.6667 128.267 VarianceRelated Questions
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