Sammy and Sally each carry a bag containing a banana, a chocolate bar, and a lic

Question

Sammy and Sally each carry a bag containing a banana, a chocolate bar, and a licorice stick Simultaneously, they take out a single food item and consume it. The possible pairs of food items that Sally and Sammy consumed are as follows. chocolate bar - chocolate bar licorice stick chocolate bar banana - banana chocolate bar - licorice stick licorice stick licorice stick chocolate bar - banana . banana - licorice stick licorice stick- banana banana chocolate bar Find the probability that at least one chocolate bar was eaten Co

Explanation / Answer

Total number of cases given = 9

P [ Having at least one chocolate bar ] = 1 - P [ Not having any chocolate bar ]

So,  P [ Not having any chocolate bar ] is as follows:

favourable cases: banana - licorice stick,  licorice stick - banana,  banana - banana, licorice stick- licorice stick

Total number of favourable case = 4

therefore, P [ Not having any chocolate bar ] = 4/9

So, P [ Having at least one chocolate bar ]

= 1 - P [ Not having any chocolate bar ]

=1 - 4/9

= 5/9

That is, 5/9 * 100% = 55.55% (Approx.)

None of the option matched, but I am sure what I did is completely correct!

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