Question 2. [4 Marks] Suppose that at a particular supermarket the probability o

Question

Question 2. [4 Marks] Suppose that at a particular supermarket the probability of waiting five minutes or longer for checkout at the cashier's counter is 25%. On a given day, a husband and wife decide to shop individually at the market, each checking out at different cashier counters. They both reach cashier counters at the same time. Determine the probability that a) 1 mark the woman will wait five minutes or longer b) 1 mark the husband will wait less than the wife c) 2 marks] both the husband and wife will wait less than five minutes.

Explanation / Answer

X: Probability of waiting more than equal to 5 minutes : P(X) = 0.25
a) Probability that woman waits 5 minutes or longer = P(X) = 0.25
b)Probability that husband waits less than wife = Probability husband waits less than 5 minutes = 1 - P(X) = 1 - 0.25 = 0.75
c) Since both the husband and wife are checking out at different cashier counters their waiting time is independent. So the probability that both of them wait less than 5 minutes =

P(husband waits < 5 min) . P(wife waits < 5 minutes) = (1-P(X)) . (1-P(X)) = (1-P(X))2 = 0.752 = 0.5625

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.