In 2015, Texas led the nation in the percentage of people who lacked health insu
ID: 3070996 • Letter: I
Question
In 2015, Texas led the nation in the percentage of people who lacked health insurance (21.6% of the population) [Ref: https://www.texmed.orgTemplate.aspx?id-422821. It is known that, nationally, 5% of patients account for 50% of the costs of healthcare. These are the "high cost" patients . Assume* that: Being a high cost patient and being uninsured are independent characteristics Insured and uninsured people become "patients" at the same rate The uninsured and high cost patients in Texas are evenly distributed across the state, and that high cost patients are evenly distributed across insured and uninsured patient populations What is the probability that a patient in a Texas healthcare facility will be a high cost patient who is uninsured? (10 pts) a. [These are huge and unrealistic assumptions, but let's assume them just for the purpose of this problem].Explanation / Answer
PROBABILITY THAT THE PERSON IS UNINSURED IS 0.216
PROBABILITY THAT THE PERSON IS HIGH COST PATIENT IS 0.05
HIGH COST PATIENTS ARE DISTRIBUTED EVENLY AMONG THE INSURED AND UNINSURED IE,. 50% OF THE HIGH COST PATIENTS ARE INSURED AND 50% OF THE HIGH COST PATIENTS ARE UNINSURED.
FROM THE DATA IT IS CLEAR THAT THE PROBABILITY OF AN INSURED TO BE PATIENT IS EQUALLY LIKELY TO PROBABILITY THAT THE AN UNINSURED TO BE PATIENT.
WE CAN SAY THAT PROBABILITY THAT A PERSON IS PATIENT IS 0.5
BEING HIGH COST AND BEING UNINSURED ARE INDEPENDENT EVENTS.
PROBABILITY THAT A PATIENT IN A TEXAS HEALTHCARE FACILITY WILL BE A HIGH COST PATIENT AND UNINSURED = 0.216* 0.05*0.5*0.5 = 0.0027
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