1. A Los Vegas handicapper can correctly predict the winning professional footba
ID: 3070337 • Letter: 1
Question
1. A Los Vegas handicapper can correctly predict the winning professional football team 70% of the time. What is the probability that she is wrong in her next prediction?
2. For the same handicapper described in Exercise 1, find the probability that she is correct in each of her next two predictions.
3. Estimate the probability that a randomly selected prime-time television show will be interrupted with a news bulletin.
4. When conducting a clinical trial of the effectiveness of a gender selection method, it is found that there is a 0.342 probability that the results could have occurred by chance. Does the method appear to be effective?
5. If what is the value of ? P(A)P (A) = 0.4,
In Exercises 6–10, use the following results: In the judicial case of United States v. City of Chicago, discrimination was charged in a qualifying exam for the position of Fire Captain. In the table below, Group A is a minority group and Group B is a majority group.
Passed Failed
Group A 10 14
Group B 417 145
6. If one of the test subjects is randomly selected, find the probability of getting someone who passed the exam.
7. Find the probability of randomly selecting one of the test subjects and getting someone who is in Group B or passed.
8. Find the probability of randomly selecting two different test subjects and finding that they are both in Group A.
9. Find the probability of randomly selecting one of the test subjects and getting someone who is in Group A and passed the exam.
10. Find the probability of getting someone who passed, given that the selected person is in Group A.
Explanation / Answer
Solution:-
1) The probability that she is wrong in her next prediction is 0.30.
P(Correct) = 0.70
P(Wrong) = 1 - 0.70
P(Wrong) = 0.30
2) The probability that she is correct in each of her next two predictions is 0.49.
p = 0.70, n = 2, x = 2
By applying binomial distribution
P(x,n) = nCx*px*(1-p)(n-x)
P(x = 2) = 0.49
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