Stock prices: Following are the closing prices for a certain stock during June a

Question

Stock prices: Following are the closing prices for a certain stock during June and July of a certain year June July 472.68 472.08 454.26 444.95 482.37491.34 494.02 459.61 466.18 481.59 493.37 498.72 485.52 484.78 474.02 477.50 484.81 490.06 488.97 492.63 487.01 488.50 483.19 497.99 488.56 484.35 484.99 484.85 439.49 436.55 Download data Part 1 out of 2 Find the population standard deviation and variance for the prices in June. Round the answers to three decimal places. The population standard deviation for the prices in June is The population variance for the prices in June is An insurance company reported that the mean score on a driving test was 84.9 with a standard deviation of 5.8 points. The test scores are approximately bell-shaped. Part 1 out of 2 Estimate the percent of participants in the test who had scores between 79.1 and 90.7. Approximately (select) of participants had scores between 79.1 and 90.7 68% 75% 88.9% 95% all or almost all NEXT

Explanation / Answer

Solution1:

June <- c(472.68,472.08,454.26,444.95,482.37,
493.37,498.72,485.52,484.78,474.02,
487.01,488.50,483.19,497.99,488.56)
print(June)
sd(June)
var(June)

Output:

> print(June)
[1] 472.68 472.08 454.26 444.95 482.37 493.37 498.72 485.52 484.78 474.02 487.01 488.50 483.19
[14] 497.99 488.56
> sd(June)
[1] 15.013
> var(June)
[1] 225.3903

populaton standard deviation for the prices in June is  15.013

population variance for the prices in june is 225.390

Solution2:

mean=84.9

sd=5.8

mean-sd=84.9-5.8=79.1

mean+sd=84.9+5.8=90.7

Accordig to empirical rule it is

68% of the distribution lies within one stddeviation of the mean

ANSWER:68%

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