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1 of 1 In humam beings, the absence of molars is nherited as a domieant trait. I

ID: 3069569 • Letter: 1

Question

1 of 1 In humam beings, the absence of molars is nherited as a domieant trait. If two hetarozygotes have four children, what is the Assuming a 1:1 sex ratio, what is the probability that five chaldren produced by the same parents will consist of ) three daughters and two sos b) alternating sexes, starting with a son? c) altemating sexes? d.) all daughters? e) all the same sex ) at least four daughters g) a daughter as the eldest child and a son a) all will have no molars? b.) three will have no molars and one will have molars? ) the first two will have molars and the second two will have no molars? 5) Galactosemia is inberiled as a recessive trait a.) one of four children will be affected If two normal heterozygotes produoe children, wbat is the chance dat as the youngest? 2) Phenylthiocarbamide (PTC) tasting is b.) three children will be born in this order dominant (T) to montasting O If a taster woman with a nontaster father produces children with a taster man, and the man previcusly had a nontaster daughter,what would be the probability that a) their first child would be a nootaster? b.) their first child would be a ontaster normal boy, affected girl, affected boy? Mendel self-fenilized pea plants with round and yellow peas In the mext generation he recovered the following nambers of peas 315 round and yellow peas 108 round and preen peas 101 wrinkled and yellow peas 32 vrinkled and green peas a) What is your bypothesis about the 7) c.) if they had six children, they would have two nontaster sons, two nontaster daughters, and two taster sons d.) their fourth child would be a taster genetic control of the phenotype? Do the data support this hypothesis? 3) On the average, about one child in every ten thousand live births in the United States has phenylketonuria (PKU) What is the probability that a) the next child bon in a Boston hospital 8) Two curly-winged fies, when mated produce sixty-one curly and thirtyfive straight-winged progeny. Use a chi-square test to determine whether these umbers fita 3:1 ratio will have PKU? b.) after that child with PKU is borm, the next child born will have PKU c) two children bon in a row will have 9) A short winged, dark-bodied fy is crossed with a long-winged, tan-bodied fly. All the Fi progeny are long-winged and tan-bodied F, flies are ecrossed among themselves to yield 84 long-winged, tan-bodied flies: 27 long-winged dark-bodied aies 35 shot- winged, tan-bodied lies; and 14 short- winged, dark-bodied flies 4) PKU and albinism are two autosomal recessive disorders, ulinked in human beings. If two people, cach heterozyBous for both traits, produce a child, what is the chance of them having a child with a) PKU? b) either PKU or albinism? c.) both traits? What ratio do you expect in the Use the chi-square test to evaluate your hypothesis. Is the observed ratio within the expected range? b)

Explanation / Answer

1) P(male) = P(female) = 0.5

a) P(3 daughters and 2 sons) = 5C2 x 0.53 x 0.52

= 10 x 0.55

= 0.3125

b) Let S indicate son and D indicate daughter.

P(S,D,S,D,S) = 0.55

= 0.03125

c) P[(S,D,S,D,S) or (D,S,D,S,D)] = 2x0.55

= 0.0625

d) P(D,D,D,D,D) = 0.55

= 0.03125

e) P[(D,D,D,D,D) or (S,S,S,S,S)] = 2x0.55

= 0.0625

f) P(daugheter as eldest and son as youngest) = 0.5 x 1 x 1 x 1 x 0.5

= 0.25