QUESTION/PROBLEM . IF YOU HAVE THESE 17 DATA AND YOU NEED 6 CLASSES, STATE THE C

Question

QUESTION/PROBLEM . IF YOU HAVE THESE 17 DATA AND YOU NEED 6 CLASSES, STATE THE CLASS WIDTH IN ITS PROPER FORMAT 1,3,5,7,9,22,33,44,55,66,87,88,89,91,92,95,96 (I AM NOT ASKING FOR YOU TO BUILD A TABLE, I ONLY WANT TO KNOW THE CLASS WIDTH-CONSULT THE POWER POINTSROUND APPROPRIATELY | IF YOUR LOWEST DATA VALUE = 25 AND YOUR HIGHEST DATA VALUE = 99, STATE THE RANGE OF YOUR DATA IN ITS PROPER FORMAT NO TABLE-JUST A SINGLE VALUE 2. IN QUESTION 1, IF WE WERE TO BUILD ATABLE, WHAT WOULD BE THE FREQUENCY BETWEEN A LOWER CLASS LIMIT OF 33 AND AN UPPER CLASS LIMIT OF 48 3. YOU ONLY NEED TO LOOK AT THE DATA SCORES TO ANSWER THIS QUESTION FILL IN ONLY THE BLANK VALUE IN THIS CHART CONSULT THE POWER POINTS OR THE WORKSHEETS TO DO THIS 4. CLASS CLASS LOWER UPPER CLASS LOWER UPPERCLASS LIMIT | LIMIT | BOUNDARY |BOUNDARY! WIDTH | MIDPOINT I FREQUENCY CLASS CLASS 65 80 FILL IN ONLY THE BLANK VALUE IN THIS CHART

Explanation / Answer

(1)

Minimum data value = 1

Maximum data value = 96

So,

Range = 96 - 1 = 95

Number of classes = 6

So,

Class width = Range/ Number of classes = 95/6 = 15.8333

Since the width is to be a whole number for easily forming the classes:

Class width = 16

(2)

Lowest data value = 25

Highest data value = 99

Range = Highest - Lowest = 99 - 25 = 74

(3)

Frequency of class with Lower class limit = 33 and upper class limit = 48 is given by: 2

(4)

CLASS      CLASS      CLASS LOWER    CLASS    CLASS    CLASS     FREQUENCY

LOWER    UPPER    BOUNDARY    UPPER WIDTH MIDPOINT

LIMIT            LIMIT                                    BOUNDARY

65                80            64.5                         80.5             15           72.5                  1

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