stics Score: 0 of 1 pt L ) 4,21 of 40 (19 complete- HW Score: 40.63%, 16.25 of 4
ID: 3068717 • Letter: S
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stics Score: 0 of 1 pt L ) 4,21 of 40 (19 complete- HW Score: 40.63%, 16.25 of 40 pts 5.3.31 Question Help In a survey of women in a certain country (ages 20-29), the mean height was 63.3 inches with a standard deviation of 2.67 inches. Answer the following questions about the specified normal distribution. (a) What height represents the 95th percentile? (b) What height represents the first quartile? (a) The height that represents the 95th percentile isnches. Round to two decimal places as needed) Incorrect:3 Enter your answer in the answer box and then click Check Answer emainingExplanation / Answer
a) here as for 95th percentile critical value of z =1.645
therfefore corresponding value =mean+z*std deviaiton =63.3+1.645*2.67 =67.69 inches
( please try 67.68 inches if above comes wrong and revert)
b)
for first quartile z score =-0.67
therefore corresponding value =mean+z*std deviation =61.51
( please try 61.50 inches if above comes wrong and revert)
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