TABLE 2.10 Nurse Sick Nurse Sick Nurse Sick Number Days Number Days Number Days
ID: 3067846 • Letter: T
Question
TABLE 2.10 Nurse Sick Nurse Sick Nurse Sick Number Days Number Days Number Days 15 16 17 18 10 12 13 14 7 20 21 TABLE 2.11 App. App. Numb. Gender Ws Wp Numb. Gender Ws Wp m 220 225 f 135 137 f 180 201 m 210 205 f 145 144 f 131 133 m 177 180 m 135 135 m 183 180 m 165 166 f 160 166 m 178 180 m 155 152 f 155 154 f 130 128 165 16 m 215 210 m 190 186 m 158 160 20 f 165 160 21 f 120 118 22 m 173 170 23 m 188 195 24 m 180 195 25 10 35 137 26 12 13 14 15 m 155 155 m 190 195 28 m 187 27 185 29 154 156 30Explanation / Answer
At first we make the column of number of sick days (say d ) in a increasing order.
FINDING FREQUENCY: To find freq. we take the values of d and find the no. of nurse for each d from the given data.
FINDING RELATIVE FREQUENCY : We just devide each frequency of d and divide it by the total frequency which is 21
This is called relative freq.
FINDING CUMU. FREQ.: Here i have calculated the cumu. freq. of "less than type". Which you can calculate just by adding all the frequencies of preceeding d values with the freq of that d value itself.
Like the cumu freq. of the value 4 is : frequency of 0+freq of 1+.....+freq of 4
= 1+1+2+1+1 = 6
FINDING RELATIVE CUMU. FREQ.: This is sme as the relative freq column. Just divide each cumulative freq value by the total freq. That's it.
if you have any doubts, let me know in the comment section. thank you.
sick days freq relative freq cumulative freq cumu. relative freq. 0 1 0.047 1 0.047 1 1 0.047 2 0.095 2 2 0.095 4 0.190 3 1 0.047 5 0.238 4 1 0.047 6 0.286 5 2 0.095 8 0.380 6 3 0.143 11 0.524 7 2 0.095 13 0.619 8 5 0.238 18 0.857 9 3 0.143 21 1.0 Total 21 1.0 ------ ---Related Questions
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