Question 21 of 33 Incorrect Mapoob Event A happens at the spacetime coordinates

Question

Question 21 of 33 Incorrect Mapoob Event A happens at the spacetime coordinates (1 lightsecond (ls) is the distance light moves in 1 second) - [7.30 s, 6.10 Is, 0.90 Is, 4.00 Is in the frame S, and event B happens at the spacetime coordinates 1,B, X,B, ??, z'?-(-5.5 s, 31.0 ls, 0.90 ls, 4.00 ls in another frame S, which is moving along the +x-axis at a speed u 0.650c relative to the frame S Calculate the time interval between events A and B in frame S, and in frame S Number B11.98 Number '-0.76 Incorrect. O In frame S, event B happens first then A, while in frame S' it is the opposite O In both frames S and S', event B happens first then A. O In both frames S and S', event A happens first then B O In frame S, event A happens first then B, while in frame S' it is the opposite

Explanation / Answer

tB - tA = tB' + ( v x' / C2 ) - tA / ( 1 - V2 / C2 )1/2 - tA

= [- 5.5+ ( (0.65C X 31C )/C2 / ( 1 - 0.652C2 / C2 )1/2 ] - 7.3

= 11.977

= 11.98 sec( rounded off value )

and

tB' - tA' = tB- ( tA - v x /C2 ) / ( 1 - V2 / C2 )1/2

= - 5.5 - ( 7.3 - 0.65 C X 6.1C /C2 ) / ( 1 - 0.652 C2/ C2 )1/2

= - 5.5 - ( 7.3 - 0.65 X 6.1 ) / ( 1 - 0.652 )1/2

= - 5.5 - 4.388

= - 9.8888 sec

and

in frame S, evenr B happens first then A , while in frame S ' it is the opposite.

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