OME INSERT PAGE LAYOUT FORMLLAS DATA REVIEW VIEW ACROBAT Normal 2 111.-ka\" HK-

Question

OME INSERT PAGE LAYOUT FORMLLAS DATA REVIEW VIEW ACROBAT Normal 2 111.-ka" HK- ty. Wrap Tet General Calbn Conditional Format as Neutral Formatting Table Copy" Format PainbeI Note: Answer the Question(s) by Using the TI-30XA (or other approved) Calculator. IMPORTANT: Make sure you carry all decimals until you reach your answer, then round to four decimals. Consider the following data for two independent random samples taken from two normal populations with equal variances. Find the 90% confidence interval for ?1-?2. (See exercise 11 on page 449 of your textbook for a similar problem) Sample 1 Sample 2 13 Left Endpoint Right Endpoint Click to Grade Your Work

Explanation / Answer

mean of sample 1= 9

mean of sample 2= 12

std of sample 1= 2.60768

std of sample 2= 2.36643

Pooled Variance
s2p = ((df1)(s21) + (df2)(s22)) / (df1 + df2) = 12.4 / 10 = 6.2

Standard Error
s(M1 - M2) = ?((s^2p/n1) + (s^2p/n2)) = ?((6.2/6) + (6.2/6)) = 1.43756

Confidence Interval
?1 - ?2 = (M1 - M2) ± ts(M1 - M2) = -3 ± (1.81 * 1.43756) = -3 ± 2.60198

?1 - ?2 = (M1 - M2) = -3, 90% CI [-5.60198,-0.39802].

You can be 90% confident that the difference between your two population means (?1 - ?2) lies between -5.60198 and -0.39802

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