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. Ignoring the effects of gravity on the particle, state the conditions under wh

ID: 306728 • Letter: #

Question

. Ignoring the effects of gravity on the particle, state the conditions under which the particle would continue to move in a straight line. 2. Suppose that the electric and magnetic fields are the same, but now the particle entering the slit is moving twice as fast as before. Explain what effect this would have on the forces acting on the particle. Sketch a force diagram for the particle, then draw a sketch of the path the particle would now take. 3. Suppose that the electric and magnetic fields are the same, but now the particle entering the slit is moving half as fast as before. Explain what effect this would have on the forces acting on the particle. Sketch a force diagram for the particle, then draw a sketch of the path the particle would now take. 4. A proton is accelerated through a potential difference of 2.5 kV. It enters a region between two parallel plates separated by a distance of 0.10 m and have a potential difference of 250 V. Find the magnitude and the direction of the magnetic field (oriented perpendicular to E) needed for the proton to pass undeflected between the plates.

Explanation / Answer

4)V = 2.5 kV = 2500 V ; d = 0.1 m ; Vp = 250 V

We know that

KE = q V

1/2 m v^2 = q V

v = sqrt (2 q V/m)

v = sqrt (2 x 1.6 x 10^-19 x 2500/(1.67 x 10^-27)) = 6.92 x 10^5 m/s

E = V/d = 250/0.1 = 2500 V/m

v = E/B => B = E/v

B = 2500/(6.92 x 10^5) = 3.61 x 10^-3 T

Hence, B = 3.61 mT

1)We know that the force due to electric field is:

F = q E

that due to magnetic field is:

F = q v B

In order for the particle to remain in straight line the above two forces should balance each other, so

q v B = q E

v = E/B

2)Since both the fields are same, noe the accelerating potential must have been increased to make it move twice as fast as before.

3)Now the accelerating potential must have been reduced.