ent PRINTER VERSION BACK NEXT Chapter 6, Section 2-CI, Exercise 084 Use the t-di

Question

ent PRINTER VERSION BACK NEXT Chapter 6, Section 2-CI, Exercise 084 Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed A 90% confidence interval for using the sample results F-135.5, s 50.8, and n-50 Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places. point estimate - margin of error- The 90% confidence interval is to Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT Question Attempts: 0 of 5 used SAVE FOR LATER SUBMIT ANSWER owered by Version 4.24.5.1 All Rights Reserved. A Division of 1ohn Wiley & Sons. Inc

Explanation / Answer

Here

Point estimate = x? = 135.5

Margin of error = critical test statistic * standard error of mean

Here confidence level = 90%

so critical test statistic = t49,0.10  = 1.67655

standard error of sample mean se0  = s/sqrt(n) = 50.8/sqrt(50) = 7.1842

Margin of error = 1.67655 * 7.1842 = 12.04

90% cofidence interval = (135.5 +- 12.04) = (123.46, 147.54)

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