MATH: statistic/ probalitity - need help problem with #9-25 (a, a-c) - related q
ID: 3066092 • Letter: M
Question
MATH: statistic/ probalitity
- need help problem with #9-25 (a, a-c)
- related questions
- please explain/show steps/answer to the question
Explanation / Answer
Question 3 : part (i)
number of colors = 3
P( Getting red at single trials) = 1/3
n = number of trials =3
X : number of red in three trials
Since each trial is independent of each other.
X ~ Bin( n =3 , p=1/3)
P ( At least one red in three trials) = P(X >=1)
which can be obtained in two ways
A) by using complement
P(X>=1) = 1 - P(X=0)
= 1- ( 3C0 * (1/3)0 * (2/3)3)
= 1- 0.2962 = 0.7038
P ( At least one red in three trials) = 0.7038
B) P(X> =1) = P(X=1) + P(X=2) + P(X=3)
= ( 3C1 * (1/3)1* (2/3)2)+ ( 3C2 * (1/3)2 * (2/3)1) + ( 3C3 * (1/3)3 * (2/3)0)
= ( 3 *(1/3) *(2/3)2 ) + ( 3 *(1/3)2 *(2/3) ) + ( 3 *(1/3)3 *(2/3)0 )
=0.4444 + 0.2222 + 0.0370
= 0.7038
The first way easier than second way i.e by using complement ( beacuse we have to find probability at one point.)
Part ii)
n = total number of households = 1060
a) Number of household earned over $ 85000 = 230
P( Earning over $ 85000) = 230 /1060 = 0.2169
b) Number household having no pets = 222
P( Having no pets ) = 222/1060 = 0.2094
c) P( having a pet)
By using complement
P(Having a pet ) = 1 - P(having no pet)
P(Having a pet) = 1 - 0.2094 = 0.7906
Household income Number with premarily dogs Number with premarily cats Number with premarily birds Number with premarily horses Number with no pets Total Under $20000 64 63 69 3 70 269 $20000 to $34999 66 59 7 3 41 176 $35000 to $54999 77 66 8 4 38 193 $55000 to $84999 82 68 7 4 31 192 $85000 and over $85000 97 77 9 5 42 230 Total 386 333 100 19 222 1060Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.