Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Let X be a standard normal random variable. Find P(-1.20 < X < 1.74). Express yo

ID: 3065765 • Letter: L

Question

Let X be a standard normal random variable. Find P(-1.20 < X < 1.74). Express your answer as a decimal.

A radar unit is used to measure speeds of cars on a motorway. The speeds are normally distributed with a mean of 90 km/hr and a standard deviation of 10 km/hr. What is the probability that a car picked at random is travelling at more than 100 km/hr?

A survey by the National Retail Federation found that women spend on average $146.21 for the Christmas holidays. Assume the standard deviation is $29.44. Find the percentage of women who spend less than $160.00. Assume the variable is normally distributed.

Each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard deviation is 2 pounds. If a household is selected at random, find the probability of its generation between 27 and 31 pounds per month.

The national average SAT score (for Verbal and Math) is 1028. If we assume a normal distribution with standard deviation 92, what is the probability that a randomly selected score exceeds 1200?

To qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 and a standard deviation of 20. Find the lowest possible score to qualify.

The average price of a personal computer is $949. If the computer prices are normally distributed with a standard deviation of $100, the least expensive 10% of personal computers cost less than what amount? Round your answer to the nearest dollar.

Explanation / Answer

(1)

Data given:

Mean, m = 0

Standard Deviation, S = 1

At X = -1.20, we have:

z = (X-m)/S = (-1.20-0)/1 = -1.2

The corresponding p-value for this z-score is:

p1 = 0.115

At X = 1.74, we have:

z = (X-m)/S = (1.74-0)/1 = 1.74

The corresponding p-value for this z-score is:

p2 = 0.959

So the reqd probability is:

p = p2-p1 = 0.959-0.115 = 0.844

Hope this helps !