l Sprint LTE 04:39 WebWorks Website unit-3-chpt07-sec7-2 4 Unit-3-CHPTO7- Sec7-2
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l Sprint LTE 04:39 WebWorks Website unit-3-chpt07-sec7-2 4 Unit-3-CHPTO7- Sec7-2: Problem 4 Prev Up Next (2 pts) Beth wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend their home basketball games. How large of a sample must she have to get a margin of error less than 0.03? [To find n, use the value p 1/2 for the sample proportion and the values for z from a z-table or t-table.] Round to the smallest integer that works.] n- Preview Answers Submit Answers You have attempted this problem 0 times. You have unlimited attempts remaining Email instructor
Explanation / Answer
ME = 0.03
P = 1/3 = 0.5
Z Value at 90% = 1.645
ME= z * sqrt(P*(1-P)/n)
0.03 = 1.645 * sqrt(0.5*0.5/n)
n = 751.6736
n = 752
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